tolong jawabannya yg benar pake jalan

Eksponen

(abc)^-3
= 1/(abc)³
= 1/(a³b³c³) ✔

3(2a²b)^-4
= 3/(2a²b)⁴
= 3 / (2⁴ (a²)⁴ b⁴)
= 3/(16a^8 b⁴) ✔