suatu kerucut memiliki diameter alas 14cm dan tinggi 24cm luas permukaan kerucut adalah........satuan luas

d = 14 cm
r = 1/2 d = 7 cm
t = 24 cm

[tex]s ^{2} = \sqrt{r ^{2} + t ^{2} } [/tex]
[tex]s ^{2} = \sqrt{24 ^{2} + 7 ^{2} } [/tex]
[tex]s ^{2} = \sqrt{576 + 49} [/tex]
[tex]s ^{2} = \sqrt{625} [/tex]
[tex]s = 25cm[/tex]

L = phi × r (r + s)
L = 22/7 × 7 (7 + 25)
L = 22(32)
L = 704 cm^2 /Satuan Luas