Tolong 1-6 pake cara

1) f(x) = 2x^4 + 3sin x
f'(x) = 8x^3 +3cos x
2) f(x) = 5cos x -1/2x^2
f'(x) = -5sin x -x
3) f(x) = 4sin x -3cos x
f'(x) = 4cos x + 3sin x
4) f(x) = 6 tan x
f'(x) = 6 sec^2 x
5) f(x) = sin x (3-cos x)
f'(x) = (cos x.(3-cos x)+(sin x .sin x)
= 3cos x -cos^2 x + sin^2 x
= 3cos x -cos^2 x +(1-cos^2 x)
= -2cos^2 x + 3cos x + 1
6) f(x) = sin x / x
f'(x) = (cos x . x - cos x)/x^2
= (x.cos x - cos x)/ x^2
= { cos x ( x -1) } / x^2