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9.]
1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃
1/Rₚ = ⅓ + ⅛ + ¹/₂₄
1/Rₚ = 12/24
Rₚ = 24/12 Ω
Rₚ = 2 Ω

10.]
R₁ = R₂ = R = 2 Ω
Rₚ = R/n [karena R sama]
Rₚ = 2/2
Rₚ = 1 Ω
Rab = 1 Ω

i = V / R
i = 12 / 1
i = 12 A

i₁ = i₂ karena jumlah hambatam mereka sama
i₁ = i₂ = i / 2
=> 12/2
=> 6 A

11.]
Rₚ untuk R₁ dan R₂
Rₚ = R/n
Rₚ = 5/2 Ω

Rₛ untuk R₃ dan R₄

Rₛ = nR [karena hambatannya sama]
Rₛ = 2 • 5
Rₛ = 10 Ω

Jadi
1/Rₜₒₜ = 1/Rₚ + 1/Rₛ
1/Rₜₒₜ = 2/5 + 1/10
1/Rₜₒₜ = 5/10
Rₜₒₜ = 2 Ω

i = V / R
i = 6 / 2
i = 3 A

a. Rₚ utk R₁ dan R₂ [diatas]
Rₚ = 5/2 Ω

b. i dibagi ke Rₚ dan Rs , perbandingannya
i₁ : i₂ = 1/Rₚ : 1/Rₛ
i₁ : i₂ = 2/5 : 1/10
i₁ : i₂ = 4
i₁ = 4i₂

Maka
i₁ + i₂ = 3 [Hk. Kirchoff]
4i₂ + i₂ = 3
5i₂ = 3
i₂ = 3/5 A
i₂= 0,6 A

Maka i₁ = 4i₂
i₁ = 4 • 3/5
i₁= 12/5 A
i₁ = 2,4 A

c. Rₛ untuk R₃ dan R₄ [lihat diatas]
Rₛ = 10 Ω

d.
i₂ = 0,6 A [lihat diatas bagian b]

e. Rₜₒₜ = 2 Ω [lihat diatas]

f. i = 3 A [lihat diatas]

12.
ε = 4 V
r = 1 Ω
R = 5 Ω

i = _ ?

Cari dlu ∑ ε dan ∑ r
∑ ε = n • ε
= 3 • 4 = 12 V

∑ r = n • r
∑ r = 3 • 1 = 3 Ω

maka
i = (∑ ε) / (∑ r + R)
i = 12 / (3 + 5)
i = 12 / 8 A
i = 1,5 A

13.]
R₁ = 3 Ω
R₂ = 6 Ω
Rₛ = R₁ + R₂
Rₛ = 3 + 6
Rₛ = 9 Ω

ε = 4 V
∑ ε = n • ε
= 3 • 4
= 12 V

i = ∑ ε / Rₛ
i = 12/9 A
i = 1,33 A