tolong diisibersama caranya ya!!!! 3x-7y-19=0 5x-2y-8=0 dijwb dgn metode eliminasi,substitusi,dan metode gabungan antara eliminasi dan substitusi... dibantu ya

3x - 7y - 19 = 0
5x - 2y - 8 = 0
a) Eliminasi
* Untuk mencari y
=> 3x - 7y = 19.............(dikali 5)
     5x - 2y = 8..............(dikali 3)

=>15x - 35y = 95
    15x - 6y = 24 _
     -29y = 71
       y = -71/29

* Untuk mencari x
=> 3x - 7y = 19...............(dikali 2)
     5x - 2y = 8................(dikali 7)

=> 6x - 14y = 38
    35x - 14y = 56 _
   -29x = -18
       x = -18/-29 = 18/29

b) Substitusi
=> 3x - 7y = 19..............(persamaan 1)
     5x - 2y = 8...............(persamaan 2)

Persamaan 1 => 3x - 7y = 19
                         -7y = -3x + 19
                           y = -3/-7 x + 19/-7
                           y = 3/7 x - 19/7

Substitusi persamaan y= 3/7 x - 19/7 ke persamaan 5x - 2y = 8
=> 5x - 2y = 8
= 5x - 2 (3/7 x - 19/7) = 8
= 5x -6/7 x + 38/7 = 8
29/7 x + 38/7 = 8
29/7 x = 8 - 38/7 = 18/7
x = 18/7  = 126/29 = 18/29
      29/7

Substitusi nilai x ke persamaan 1
=> 3x - 7y = 19
= 3 (18/29) - 7y = 19
= 54/29 - 7y = 19
= -7y = 19 - 54/29 = 497/29
= y = 497/29
             -7
 y = 497/203 = -71/29

c) Eliminasi dan substitusi
=>3x - 7y = 19.............(dikali 5)
     5x - 2y = 8..............(dikali 3)

=>15x - 35y = 95
    15x - 6y = 24 _
     -29y = 71
       y = -71/29

Substitusi nilai y = -71/29 ke persamaan 3x - 7y = 19
=> 3x - 7y = 19
= 3x - 7 (-71/29) = 19
= 3x + 497/29 = 19
3x = 19 - 497/29 = 54/29
x = 54/29 = 54/87 = 18/29
         3

Semoga bermanfaat ^_^