Matematika

Pertanyaan

nilai 6 log 60 bila 2 log 3=a dan 3log 5= b

1 Jawaban

  • 2log6 = 2log(2x3)
    =2log2 + 2log3
    =1+a

    5log6 = 5log(2x3)
    =5log2 + 5log3
    =5log3 x 3log2 + 5log3
    =1/b x 1/a + 1/b
    =1/ab + 1/b
    =(a+1)/ab

    6log60 = 6log(6x10)
    =6log6 + 6log10
    =1 + 6log(2x5)
    =1 + 6log2 + 6log5
    =1 + 1/(2log6) + 1/(5log6)
    =1 + 1/(a+1) + 1/[(a+1)/ab]
    =1 + 1/(a+1) + ab/(a+1)
    =1 + (1 + ab)/(a + 1)

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