Jika α dan β adalah akar akar persamaan kuadrat 2x²-x+3=0 maka nilai 3α²β+3αβ² adalah

• α+β = -(-1)/2
= 1/2

• αβ = 3/2

• 3α²β+3αβ² = 3αβ(α+β)
= 3(3/2)(1/2)
= 3(3/4)
= 9/4

2x² - x + 3 = 0
a = 2, b = -1 dan c = 3

α + β = 1/2
αβ = 3/2
α² + β² = (α + β)² - 2αβ = 1/4 - 3 = -11/4

= 3α³β + 3αβ³
= 3αβ(α² + β²)
= 3(3/2)(-11/4)
= -99/8