[tex]integral 2x \sqrt{x2 - 2dx} [/tex]

InTegraL

Misal :
u = x² - 2
du/dx = 2x
2x dx = du

∫2x√(x² - 2) dx
= ∫u^1/2 du
= 1/(3/2) u^(3/2) + C
= 2/3 u√u
= 2/3 (x² - 2)√(x² - 2) + C ✔