Jika a=2,b=3,dan c=4,hitulanglah a5+b-3c (2a-4b)c Kuadrat-3a+ab Kuadrat(ab+ac+bc)

(2)5+3-(3)4[(2(2)-4(3)]×4^2-3(2)+(2×3)^2(2×3-2×4+3×4)
= 10+3-12(4-2)16-6+6^2(6-8+12)
=1(-8)10+36(14)
=(-7)10+36(14)
=-70+504
= 434

a5+b-3c
=(2)5+3-3(4)
=10 + 3 -12
= 1

(2a-4b)c
= (2(2)-4(3))(4)
= (4-12)(4)
= -8(4)
= -32

(-3a+ab)²
= (-3a+ab)(-3a+ab)
= 9a² - 3a²b - 3a²b +a²b²
= 9a²-9a²b+a²b²
= 9(2)²-9(2)²(3)+(2)²(3)²
= 9(4)-9(4)(3)+(4)(9)
= 36-9(12)+36
= 36-108+36
=-42