Log2x – 7 logx + 7 = 1 – 2 logx
Matematika
puspitamila27
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Log2x – 7 logx + 7 = 1 – 2 logx
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1. Jawaban Anonyme
jawab
log² x - 7.log x + 7 = 1 - 2 log x
log² x - 7 log x + 2 log x + 7 - 1 = 0
log² x - 5 log x + 6 = 0
(log x - 3)(log x - 2) = 0
log x - 3 = 0 atau log x - 2 = 0
log x = 3 atau log x = 2
x = 10³ atau x =10²
x = 1.000 atau x = 100