Tolong kak di bantu

2x + y ≤ 6
Batas Daerah Penyelesaian : 2x + y = 6
x = 0 , y = 6 (0 , 6)
y = 0 , x = 3 (3 , 0)

x + 2y ≥ 6
BDP : x + 2y = 6
x = 0 , y = 3 (0 , 3)
y = 0 , x = 6 (6 , 0)

Titik Potong
x + 2y = 6
2x + y = 6 |x 2|
–––––––––––– –
-3x = -6
x = 2

x + 2y = 6
2y = 6 - x
2y = 6 - 2
2y = 4
y = 2

Titik Potongnya (2 , 2)

Selanjutnya , titik² yg akan diuji ada pd gambar
f(x , y) = 2x + 3y

f(3 , 0) = 2(3) = 6
f(6 , 0) = 2(6) = 12
f(2 , 2) = 2(2) + 3(2) = 10

Jadi nilai minimumnya 6 [B]