f(x)=x+2 g(x)=3x-4 a).(fog)(x)= b).(fog)(-2)= c).(gof)(x)= d).(gof)(2)=
Matematika
putsun
Pertanyaan
f(x)=x+2
g(x)=3x-4
a).(fog)(x)=
b).(fog)(-2)=
c).(gof)(x)=
d).(gof)(2)=
g(x)=3x-4
a).(fog)(x)=
b).(fog)(-2)=
c).(gof)(x)=
d).(gof)(2)=
1 Jawaban
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1. Jawaban gracenoverriel
>> FunGsi
f(x) = x + 2
g(x) = 3x - 4
a). (fog)(x) ?
(fog)(x) -> x pada fungsi f(x) diganti menjadi g(x) -> f(g(x)) -> f(3x - 4) Artinya :
(fog)(x) = (3x - 4) + 2
(fog)(x) = 3x - 2
b). (fog)(-2) ?
(fog)(-2) -> masukkan nilai x = -2 ke persamaan a).
(fog)(-2) = 3(-2) - 2
(fog)(-2) = - 6 - 2
(fog)(-2) = - 8
c). (gof)(x) ?
x di persamaan fungsi g(x) di ganti menjadi f(x) -> g(f(x)) -> g(x + 2). Artinya :
(gof)(x) = 3(x + 2) - 4
(gof)(x) = 3x + 6 - 4
(gof)(x) = 3x + 2
d). gof(2) ?
Masukkan nilai x = 2 ke persamaan c).
(gof)(2) = 3(2) + 2
(gof)(2) = 6 + 2
(gof)(2) = 8
Semoga membantu