NILAI SIN 105 + COS 15 = Mohon bantuannya ya!

sin 105
sin (45+60)= sin 45°.cos 60°-cos 45°.sin60°
= (1/2 akar 2×1/2)-(1/2 akar 2×1/2 akar3)
=1/4 akar 2-1/4 akar 6
=1/4 (akar 2-akar 6)
= 1/4 akar -4

cos 15
cos (45-30) = cos 45.cos 30+sin 45.sin 30
= (1/2 akar 2×1/2 akar 3)+(1/2 akar 2×1/2)
= 1/4 akar 6 + 1/4 akar 2
= 1/4 (akar 6+akar 2)
= 1/4 akar 8

maka sin 105+cos 15 = 1/4 akar -4 + 1/4 akar 8
= 2/4 akar 4
= 1/2 akar 4



maaf kalau salah^^