(5a + 4)y + 8x = 12 Gradien = 1 Tentukan a

[tex](5a + 4)y + 8x = 12 \\ (5a + 4)y = - 8x + 12 \\ y = - \frac{8x}{5a + 4} + \frac{12}{5a + 4} [/tex]

[tex]m= - \frac{8}{5a + 4} \\ 1 = - \frac{8}{5a + 4} \\ 5a + 4 = - 8 \\ 5a = - 12 \\ a = - \frac{12}{5} [/tex]