turunan rantai dari 2x3 + 4y3 + 8 = 0

[tex]6 {x}^{2} + 12 {y}^{2} \frac{dy}{dx} = 0 \\ 12 {y}^{2} \frac{dy}{dx} = - 6 {x}^{2} \\ \frac{dy}{dx} = - \frac{6 {x}^{2} }{12 {y}^{2} } \\ \frac{dy}{dx} = - \frac{ {x}^{2} }{2 {y}^{2} } [/tex]