300 gram air bersuhu 90°C dituangkan ke dalam 100 gram air bersuhu 26°C. Berapa Suhu akhir campuran

dik
m1 = 300 gr
m2=100 gr
T1 = 90° c
T2 = 26 °c
c air = 1 kal /g°c


jawab

Qlepas = Qterima
m1.c.∆T1 = m2.c.∆T2
300. 1. (90° - Tc) = 100 . 1 . ( Tc -26°)
27000 - 300Tc = 100Tc - 2600
27000+2600 = (300+100)Tc
29600 = 400 Tc
Tc = 29600/ 400
= 74°c