Matematika

Pertanyaan

Kak dibantu yaa,,, please
Kak dibantu yaa,,, please

2 Jawaban

  • nilai determinan matriksnya = 0, berarti
    (3x - 1)(x + 2) - 3(x + 1) = 0
    3x² + 6x - x - 2 - (3x + 3) = 0
    3x² + 5x - 2 - 3x - 3 = 0
    3x² + 2x - 5 = 0
    (3x + 5) (x - 1) = 0
    x = -5/3   atau   x = 1
  • Bab Matriks
    Matematika SMA Kelas X

    [ (3x - 1)          3] = 0
    [ (x + 1)   (x + 2)]

    (3x - 1) . (x + 2) - 3 (x + 1) = 0
    3x² + 6x - x - 2 - 3x - 3 = 0
    3x² + 2x - 5 = 0
    (3x + 5) (x - 1) = 0
    3x + 5 = 0
    3x = -5
    x = -5/3

    x - 1 = 0
    x = 1

    -5/3 atau 1

    Jawabannya C