Jika 2log3=a dan 3log5=b, maka 4log45=... A. a(b+2) B. a/2(b+2) C. b/2(a+2) D. b(a+2) E. (a+2) (b+2)

[tex]2 log(3) = a \\ 3 log(5 ) = b \\ 2 \div 3 log_{5}(3) \\ 4 log(45) = \\ 4 log(9 \times 5) \\ 4(2 log(3) + log(5) ) \\ 4(a + b \div 3) \\ (12a + 4b) \div 3[/tex]
langkanya sih begini

kalau soalmu begitu