satu lgi ni kaa. pake cara yaaa:v

Kita hitung dlu rangkaian pengganti dri R2 dan R3 (paralel)
1/Rp = 1/R2 + 1/R3 = 1/3 + 1/6 = 3/6
1/Rp = 3/6 →→ Rp = 6/3 = 2ohm

Sekarang hitung R1 dan rangakain pengganti 2ohm (seri)
Rs = R1 + Rp = 4ohm + 2ohm = 6ohm

V = I.R
6V = I.6ohm
I = 6V/6ohm = 1Ampere