tolong yaa makasish.. pakai cara ya

2 dadu, n(S) = 36
E1 kejadian kedua mata dadu <= 6
E1 = { (1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(4,1),(4,2),(5,1)}. n(E) = 15
P(E1) = n(E1)/n(S)
= 15/36
= 5/12
b) E2= kejadian kedua mata dadu prima
E2 = { ( 2,2),(2,3),(2,5),(3,2),(3,3),(3,5),(5,3),(5,2),(5,5). n(E2) = 9
P(E2) = n(E2)/n(S)
= 9/36
= 1/4