Matematika

Pertanyaan

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2 Jawaban

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    Gambar lampiran jawaban BerukBerpose
  • 1)
    a.
    y = -1/2x+4
    kedua ruas dikalikan 2
    2y = -x + 8
    x + 2y - 8 = 0

    koef x = 1
    koef y = 2
    konstanta = -8

    b.
    3x-4y-2 = 0
    koef x = 3
    koef y = -4
    konstanta = -2

    c.
    -x+2y = -1
    -x+2y + 1 = 0
    dikali -1
    x - 2y - 1 = 0
    koef x = 1
    koef y = -2
    konstanta = -1

    3)
    a.
    2x-3y = 7
    2x+y = 3
    ________ -

    -4y = 4
    y = -1

    2x-3y = 7
    2x-3(-1) = 7
    2x+3 = 7
    2x = 4
    x = 2

    b.
    x-y = 1 |×3|
    3x-y = 9 |×1|

    3x-3y = 3
    3x-y = 9
    _______ -
    -2y = -6
    y = 3

    x-y = 1
    x-(3) = 1
    x = 4