Hambatan pengganti pada rangkaian diatas sebesar. ... Ohm A. 25,0 C. 17,5 B. 22,5 D. 15,0

1/Rp = 1/R1 + 1/R2
1/Rp = 1/5 + 1/5
1/Rp = 2/5
Rp = 5/2 = 2,5 Ohm

1/Rp = 1/R3 + 1/R4
1/Rp = 1 /10 + 1/10
1/Rp = 2/10
Rp = 10/2 = 5 Ohm

Rs = R5 = 7,5 Ohm

Hambatan Pengganti = 2,5 + 5 + 7,5 = 15 Ohm ( D )

= 1/R(paralel 1)= 1/5+1/5=2/5
R(paralel 1)= 5/2=2,5
=1/R(paralel 2)=1/10+1/10=2/10= 1/5
R(paralel 2)=5
= R(paralel 1)+R(paralel 2)+R(seri)
= 2,5+5+7,5= 15 Ohm (D)
mf klo slh :)