kak tolong di bantu untuk jawab no 11-14
Matematika
ariananta123
Pertanyaan
kak tolong di bantu untuk jawab no 11-14
1 Jawaban
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1. Jawaban cupid85
11) ( y - y1) / (y2 - y1) = ( x - x1) / ( x2 - x1)
( y - 2) / (4 - 2) = ( x - 1) / ( 3 - 1)
( y - 2) / 2 = ( x - 1) / 2
2 ( y - 2) = 2 ( x - 1)
2y - 4 = 2x - 2
2y = 2x - 2 + 4
2y = 2x + 2
y = x + 1 ( D )
12) 2y + 2x = 3
2y = - 2x + 3
m = - 2 / 2
m = - 1
syarat sejajar m1 = m2 = - 1
pers garis
y - y1 = m ( x - x1)
y - 6 = - 1 ( x - 3)
y = - x + 3 + 6
y = - x + 9 ( A )
13) 4y - 3x = 5
4y = 3x + 5
m = ¾
syarat sejajar = m1 = m2 = ¾
pers garis
y - y1 = m ( x - x1)
y - 6 = ¾ ( x + 3)
y = ¾ x + 9/4 + 6 (dikalikan 4)
4y = 3x + 9 + 24
4y = 3x + 33 ( A )