Matematika

Pertanyaan

kak tolong di bantu untuk jawab no 11-14
kak tolong di bantu untuk jawab no 11-14

1 Jawaban

  • 11) ( y - y1) / (y2 - y1) = ( x - x1) / ( x2 - x1)
    ( y - 2) / (4 - 2) = ( x - 1) / ( 3 - 1)
    ( y - 2) / 2 = ( x - 1) / 2
    2 ( y - 2) = 2 ( x - 1)
    2y - 4 = 2x - 2
    2y = 2x - 2 + 4
    2y = 2x + 2
    y = x + 1 ( D )

    12) 2y + 2x = 3
    2y = - 2x + 3
    m = - 2 / 2
    m = - 1
    syarat sejajar m1 = m2 = - 1
    pers garis
    y - y1 = m ( x - x1)
    y - 6 = - 1 ( x - 3)
    y = - x + 3 + 6
    y = - x + 9 ( A )

    13) 4y - 3x = 5
    4y = 3x + 5
    m = ¾
    syarat sejajar = m1 = m2 = ¾
    pers garis
    y - y1 = m ( x - x1)
    y - 6 = ¾ ( x + 3)
    y = ¾ x + 9/4 + 6 (dikalikan 4)
    4y = 3x + 9 + 24
    4y = 3x + 33 ( A )