⁴log²(2x-1) - ⁴log(2x-1)^5 + 6 = 0
Matematika
Vikaika1
Pertanyaan
⁴log²(2x-1) - ⁴log(2x-1)^5 + 6 = 0
1 Jawaban
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1. Jawaban yanfardian
Misalkan ⁴log(2x - 1) = a
⁴log²(2x - 1) - ⁴log(2x - 1)⁵ + 6 = 0
a² - 5a + 6 = 0
(a - 2)(a - 3) = 0
a = 2 atau a = 3
Untuk a = 2
⁴log(2x - 1) = 2
⁴log(2x - 1) = ⁴log 4²
2x - 1 = 16
2x = 17
x = 8 1/2
Untuk a = 3
⁴log(2x - 1) = 3
⁴log(2x - 1) = ⁴log 4³
2x - 1 = 64
2x = 65
x = 32 1/2
Jadi x = 8 1/2 atau x = 32 1/2.