Matematika

Pertanyaan

⁴log²(2x-1) - ⁴log(2x-1)^5 + 6 = 0

1 Jawaban

  • Misalkan ⁴log(2x - 1) = a
    ⁴log²(2x - 1) - ⁴log(2x - 1)⁵ + 6 = 0
    a² - 5a + 6 = 0
    (a - 2)(a - 3) = 0
    a = 2 atau a = 3

    Untuk a = 2
    ⁴log(2x - 1) = 2
    ⁴log(2x - 1) = ⁴log 4²
    2x - 1 = 16
    2x = 17
    x = 8 1/2

    Untuk a = 3
    ⁴log(2x - 1) = 3
    ⁴log(2x - 1) = ⁴log 4³
    2x - 1 = 64
    2x = 65
    x = 32 1/2

    Jadi x = 8 1/2 atau x = 32 1/2.

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