5logx^2 = 5log 4x + 1
Matematika
sehunn2
Pertanyaan
5logx^2 = 5log 4x + 1
1 Jawaban
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1. Jawaban Anonyme
5logx^2 - 5log4x + 1 = 0
5logx^2 - 5log4x + 5log5 = 0
5log( x^2 - 4x + 5) = 5log1
x² - 4x + 5 = 1
x² - 4x + 4 = 0
(x - 2)² = 0
jadi x - 2 = 0 .... x = 2