Matematika

Pertanyaan

5logx^2 = 5log 4x + 1

1 Jawaban

  • 5logx^2 - 5log4x + 1 = 0
    5logx^2 - 5log4x + 5log5 = 0
    5log( x^2 - 4x + 5) = 5log1
    x² - 4x + 5 = 1
    x² - 4x + 4 = 0
    (x - 2)² = 0
    jadi x - 2 = 0 .... x = 2

Pertanyaan Lainnya