semoga jasanya dibalas allah pakek jalan

nomot 1) jika f(x) = x +1 , maka f(x²) - 2f(x) =
f(x²) - 2f(x)
= x² + 1 - 2(x + 1)
= x² - 2x - 2 + 1
= x² - 2x - 1

nomor 2) diketahui f(x) = 3x - 6 dan g(x) = 2x + a jika (f °g)(x) = (g°f)(x) , maka a =
(f °g)(x) = (g°f)(x)
f(g(x)) = g(f(x))
3(2x + a) - 6 = 2(3x - 6) + a
6x + 3a - 6 = 6x - 12 + a
3a - 6 = -12 + a
3a - a = -12 + 6
2a = -6
a = -6/2
a = -3

nomor 3) f(x) =√4x+2 dan g(x) = 2x² - 2 , maka (g ° f)(x) = 
gof(x)
= g(f(x))
= 2(√4x+2)² - 2
= 2(4x + 2) - 2
= 8x + 4 - 2
= 8x + 2

nomor 4) fungsi f(x) dan dan g(x) didefinisikan dengan f(x)= x², g(x) = 1 - 2x dan (f ° g ) (a) = 25 , nilai a = 

fog(a) = 25
f(g(a)) = 25
f(1 - 2a) = 25
(1 - 2a)² = 25
1 - 4a + 4a² = 25
4a² - 4a - 24 = 0
a² - a - 6 = 0
(a + 2)(a - 3) = 0
a = -2   atau    a = 3