Matematika

Pertanyaan

Jika sin^2x - 2cosx = 1 dimana 0

1 Jawaban

  • 2sin²x + 3cosx = 0
    2(1-cos²x) + 3cosx = 0
    2 - 2cos²x + 3cosx = 0
    2cos²x - 3cosx - 2 = 0
    (2cosx+1)(cosx-2) = 0
    (2cosx+1) = 0 
    2cosx = -1
    cosx = -1/2
    ⇒cos x = cos 120°
             x = 120°
    ⇒cos x = cos 240°
             x = 240°

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