Tentukan nilai r pada persamaan bentuk aljabaf (2×+3y)(px+qy)=rx2+23xy+12y2

(2x+3y)(px+qy)=rx^2 + 23xy + 12 y^2
=2px^2 +2qxy+3pxy+3qy^2

3q = 12
q = 4

2px^2+2(4)xy+3pxy+3(4)y^2
2px^2+8xy+3pxy+12y^2 = rx^2+23xy+12y^2

8xy+3pxy = 23xy
3pxy = 23xy-8xy
3pxy = 15xy
p = 5

2px^2+8xy+3pxy+12y^2 = rx^2+23xy+12y^2
2(5)x^2+8xy+3(5)xy+12y^2
10x^2+23xy+12y^2 = rx^2+23xy+12y^2

r = 10

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