perhatikan gambar di samping. jika AP = 3 cm, PD = 5 cm, dan BC = 10 cm. maka panjang BQ adalah.. cm.

[tex] \frac{ad}{bc} = \frac{pd}{qc} \\ \frac{3 + 5}{10} = \frac{5}{qc} \\ \frac{8}{10} = \frac{5}{qc} \\ 8qc = 50 \\ qc = 6.25\\ \\ bq = bc - qc \\ bq = 10 - 6.25 \\ bq = 3.75[/tex]
Maaf Kalau Salah