tolong ya pake cara jika [tex] \frac{ 6^{3x-y-1} }{2^{3x-y} } = \frac{9}{2} [/tex] maka [tex] ^{3x-y} log \sqrt{3 \sqrt{3} } =[/tex] ....

Question

Matematika Diposting : 2017-11-11 Diupdate : 2021-11-16 ozan09aja

Pertanyaan

tolong ya pake cara
jika [tex] \frac{ 6^{3x-y-1} }{2^{3x-y} } = \frac{9}{2} [/tex] maka [tex] ^{3x-y} log \sqrt{3 \sqrt{3} } =[/tex] ....

Answer 1

jawab

[tex] \frac{ 6^{3x-y-1}}{2^{3x-y} }\, = \frac{9}{2} [/tex]

[tex]\frac{ 6^{(3x-y)\, 6^{-1} }}{2^{3x-y} }\, = \frac{9}{2}[/tex]