dua buah dadu dilemparkan 1 kali dan diketahui mata dadu yang muncul adalah genap. Tentukan peluang munculnya mata dadu kurang dari 7

2 dadu dilempar => n(S) = 36

A = jumlah mata dadu genap < 10
2 = (1,1) = 1
4 = (1,3), (3,1), (2,2) = 3
6 = (1,5), (5,1), (2,4), (4,2), (3,3) = 5
8 = (2,6), (6,2), (3,5), (5,3), (4,4) = 5
n(A) = 1 + 3 + 5 + 5 = 14

B = jumlah mata dadu ganjil < 7
3 = (1,2), (2,1) = 2
5 = (1,4), (4,1), (2,3), (3,2) = 4
n(B) = 2 + 4 = 6

Peluang = P(A U B) = P(A) + P(B) = 14/36 + 6/36 = 20/36 = 5/9

(2,4)(4,2)(2,2)
peluang 3/36=1/12