Matematika

Pertanyaan

Diketahui cot A = 7/24 dengan A sudut lancip maka sec A + cosec A =

1 Jawaban

  • cot A = 7/24.
    cot A = x/y
    r^2 = x^2+ y^2
    r^2 = 7^2 + 24^2
    r^2 = 49+576
    r^2 = 626
    r = √625
    r = 25
    sec A + cosec A = 25/7+25/24
    = 600/168 + 175/168
    = 775/168

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