Integral 0{1 (2-3x-½x²)dx,kk bantuin dong..

jawab

₀¹∫ (2 - 3x - 1/2 x²) dx
= [2x - 3/2 x² - 1/2 . 2/3. x^(3/2)]¹₀
= [2x - 3/2 x² - 1/3 x^(3/2)]¹₀
= [2(1) - 3/2(1) - 1/3(1)] -[0]
= 1/6