f(x)=ax+b. f(-6)=32. f(4)=-8 tentukan nilai a dan b f(x)

di eliminasi
-6a+b=32<====f(-6)
4a+b=-8<====f(4)
-10a=40
a=-4

di subtitusikan
4(-4)+b=-8
-16+b=-8
b=-8+16
b=8

[tex]f(-6) = -6a+b=32 \\ ...f(4) = 4a+b=-8 \\[/tex]
eliminasi keduanya
[tex]-6a-4a=32-(-8) \\ -10a = 40 \\ a = -4\\ -6a+b=32 \\ -6(-4)+b = 32 \\ 24 +b=32 \\ b=8[/tex]