Matematika

Pertanyaan

mohon bantuannya wkwkww
mohon bantuannya wkwkww

1 Jawaban

  • No.5
    gofof(x)
    = g(fof(x))
    = g(f(f(x)))
    = g(f(√x))
    = g(√(√x))
    = (√(√x))² + 1
    = √x  + 1
    -------------------------------------------------
    No. 12
    f(x) = 2x - 3
    gof(x) = 6x + 10

    maka
    g(f(x)) = 6x + 10
    g(2x - 3) = 6x + 10
    g(x) = 6[(x + 3)/2] + 10
    g(x) = 3(x+3) + 10
    g(x) = 3x + 9 + 10
    g(x) = 3x + 19

    y = 3x + 19
    y - 19 = 3x
    (y - 19)/3 = x

    jadi g⁻¹(x) = (x - 19)/3

    ----------------------------------------------------------------------
    No. 13
    fog(x) = 10x - 8
    g(x) = 2x + 4
    mka

    f(g(x)) = 10x - 8
    f(2x + 4) = 10x - 8
    f(x) = 10 [(x - 4)/2] - 8
    f(x) = 5(x - 4) - 8
    f(x) = 5x - 20 - 8
    f(x) = 5x - 28

    y = 5x - 8
    y + 8 = 5x
    (y + 8)/5 = x
    jadi
    f⁻¹(x) = (x + 8)/5
    --------------------------------------------------------------------------
    No/ 6
    f(x) = 2x + p
    g(x) = 3x + 120
    diketahui f(g(x)) = g(f(x))

    maka
    2(3x + 120) + p = 3(2x + p) + 120
    6x + 240 + p = 6x + 3p + 120
    240 + p = 3p + 120
    4p = 120
    p = 30

    ------------------------------------------------------------------------------------------
    NO.7
    g(x) = x² - 1
    fog(x) = x⁴

    maka
    f(g(x)) = x⁴
    f(x² - 1) = x⁴
    misal
    y = x² - 1
    x² = y + 1
    x = √(y + 1)

    f(y) = [√(y + 1)]⁴
    f(y) = (y + 1)²
    f(y) = y² + 2y + 1

    f(4) = 4² + 2(4) + 1
    f(4) = 16 + 8 + 1
    f(4) = 25